In the esterification of propanoic acid with methanol in the presence of a mineral acid, which of the following are intermediate species?

\begin{matrix} \oplus O H | | C_{2} H_{5} - & C & - O H \end{matrix}

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\begin{matrix} O H | C_{2} H_{5} - & C \oplus - & O H \end{matrix}

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\begin{matrix} O H | C_{2} H_{5} - & C - & O H | O C H_{3} \end{matrix}

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\begin{matrix} O H | C_{2} H_{5} - & C \oplus - & O C H_{3} \end{matrix}

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Solution

The correct options are
A $\begin{matrix} \oplus O H | | C_{2} H_{5} - & C & - O H \end{matrix}$
B $\begin{matrix} O H | C_{2} H_{5} - & C \oplus - & O H \end{matrix}$
C $\begin{matrix} O H | C_{2} H_{5} - & C - & O H | O C H_{3} \end{matrix}$
D $\begin{matrix} O H | C_{2} H_{5} - & C \oplus - & O C H_{3} \end{matrix}$
In the esterification of propanoic acid with methanol in the presence of a mineral acid, compounds A,B,C and D are prepared in order and the final product is $\begin{matrix} O | | C_{2} H_{5} - & C - & O C H_{3} \end{matrix}$

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Similar questions

\begin{matrix} O H | C H_{3} - & C - & C_{6} H_{5} | C_{2} H_{5} \end{matrix}

O H^{⊖}

C H_{3} - C H | C_{2} H_{5} - B r

C H_{3} - B r | C | C_{2} H_{5} - C H_{3}

C H_{3} - C H | C_{2} H_{5} - C H_{2} B r

I . C_{2} H_{5} - I + {N H}_{3} ⟶ C_{2} H_{5}_{3} + I^{⊖}

I I . C_{2} H_{5} - I + \cdot \cdot P H_{3} ⟶ C_{2} H_{5}_{3} + I^{⊖}

I I I . C_{2} H_{5} - I + E t O^{⊖} ⟶ C_{2} H_{5} - O E t + I^{⊖}

I V . M e - \oplus S - {M e}_{2} + ⊖ O H ⟶ M e - O H + {M e}_{2} S

S_{N} 2

C_{2} H_{4} + H_{2} O = C_{2} H_{5} O H

{Δ H}_{f o r m}^{o} (C_{2} H_{4}) = 55, 28 K J / m o l

{Δ H}_{f o r m}^{o} (H_{2} O) = - 241.8 K J / m o l

{Δ H}_{f o r m}^{o} (C_{2} H_{5} O H) = - 235.3 K J / m o l

C H_{3} C H_{2} C H_{2} CHO, C H_{3} C H_{2} C H_{2} CH_{2} OH, C_{2} H_{5} O C_{2} H_{5}, C H_{3} C H_{2} C H_{2} C H_{3}

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