In the esterification reaction, the correct order of reactivity of alcohols is:

C H_{3} O H > C H_{3} C H_{2} O H > (C H_{3})_{2} C H O H

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C H_{3} O H > (C H_{3})_{2} C H O H > C H_{3} C H_{2} O H

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C H_{3} C H_{2} O H > (C H_{3})_{2} C H O H > C H_{3} O H

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(C H_{3})_{2} C H O H > C H_{3} C H_{2} O H > C H_{3} O H

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Solution

The correct option is B $C H_{3} O H > C H_{3} C H_{2} O H > (C H_{3})_{2} C H O H$
In the esterification reaction, the alcohol acts as a nucleophile ( $R O^{-}$ ).
The nucleophilicity order is:
$C H_{3} O^{-} > C H_{3} C H_{2} O^{-} > (C H_{3})_{2} C H O^{-}$
As the bulkiness of the nucleophilic group increases the reactivity towards esterification decreases.
Hence Option A represents the correct order.

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