In the estimation of sulphur by Carius Method, $0.468 g$ of an organic compound afforded $0.668 g$ of barium sulphate. Find the percentage of sulphar in that compound.

12.85 %

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15.66 %

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19.60 %

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25.35 %

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Solution

The correct option is C $19.60 %$
$%$ of Sulphur $= \frac{32}{233} \times \frac{M a s s o f B a S O_{4} f o r m e d}{M a s s o f o r g a n i c c o m p o u n d} \times 100$
$⟹ %$ of Sulphur $= \frac{32}{233} \times \frac{0.668}{0.468} \times 100$
$⟹ %$ of Sulphur $= 19.60 %$ (approx.)

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In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

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In the estimation of sulphur by Carius Method, 0.468 g of an organic compound afforded 0.668 g of barium sulphate. Find the percentage of sulphar in that compound.

The correct option is C 19.60%% of Sulphur =32233×Mass of BaSO4 formedMass of organic compound×100⟹% of Sulphur =32233×0.6680.468×100⟹% of Sulphur =19.60% (approx.)

In the estimation of sulphur by Carius Method, $0.468 g$ of an organic compound afforded $0.668 g$ of barium sulphate. Find the percentage of sulphar in that compound.

The correct option is C $19.60 %$
$%$ of Sulphur $= \frac{32}{233} \times \frac{M a s s o f B a S O_{4} f o r m e d}{M a s s o f o r g a n i c c o m p o u n d} \times 100$
$⟹ %$ of Sulphur $= \frac{32}{233} \times \frac{0.668}{0.468} \times 100$
$⟹ %$ of Sulphur $= 19.60 %$ (approx.)