Question

In the estimation of sulphur by Carius method, 0.468 gm of an organic sulphur compound afforded 0.668 gm of barium sulphate. Find out the percentage(in nearest integer) of sulphur in the given compound.

Answer 1

Percentage of S $=\frac{32}{233}\times \frac{WeightofBaS{O}_4\times 100}{Weightofcompound}$

$=\frac{32}{233}\times \frac{0.668\times 100}{0.468}=19.66$%

Hence, percentage of S (in nearest integer) = $20$.