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Byju's Answer

Standard XII

Chemistry

Arrhenius Acid

In the excess...

Question

In the excess of $N H_{3} (a q .), C u^{2 +}$ ions forms a deep blue complex ion ${[C u {(N H_{3})}_{4}]}^{+ 2}$ which has $K_{f} = 10^{11}$ the concentration of $C u^{2 +}$ ion in solution prepared by adding $5 \times 10^{- 3}$ moles of $C u S O_{4}$ to $0.5 L$ of $0.4 M N H_{3} (a q)$ is

\frac{5 \times 10^{- 5}}{{(36)}^{4}}

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\frac{10^{- 6}}{{(36)}^{4}}

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\frac{10^{- 5}}{{(36)}^{4}}

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\frac{10^{- 2}}{{(39)}^{4}}

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Solution

The correct option is C $\frac{10^{- 5}}{{(36)}^{4}}$

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Similar questions

Q. A test for the complete removal of

C u^{2 +}

ions from a solution of

C u^{2 +} (a q .)

is to add

N H_{3} (a q .)

. A blue colour signifies the formation of complex

[C u (N H_{3})_{4}]^{2 +}

that has

K_{f} = 1.1 \times 10^{13}

and thus confirms the presence of

C u^{2 +}

in the solution. 250 mL of 0.1 M

C u S O_{4} (a q .)

is electrolyzed by passing a current of 3.5 ampere for 1350 seconds. Then, sufficient quantity of

N H_{3} (a q .)

is added to the electrolyzed solution maintaining

[N H_{3}] = 0.1 M

. If

[C u (N H_{3})_{4}]^{2 +}

is detectable upto its concentration as low as

1 \times 10^{- 5}

. Pick the correct statement(s):

Q. If excess of

Z n

is added to

1.0 M

solution of

C u S O_{4}

, find the concentration of

C u^{2 +}

ions at equilibrium.
Given:

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

Q. If excess of

Z n

is added to

1.0 M

solution of

C u S O_{4}

, fint the concentration of

C u^{2 +}

ions at equilibrium.
Given:

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

Q. If excess of

Z n

is added to

1.0 M

solution of

C u S O_{4}

, fint the concentration of

C u^{2 +}

ions at equilibrium.
Given:

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

Q. A test for complete removal of

C u^{2 +}

(aq) is to add

N H_{3}

(aq). A blue colour signifies the formation of complex

[C u (N H_{3})_{4}]^{2 +}

having

K_{f}

= 1.1

\times

10^{13}

and thus confirms the presence of

C u^{2 +}

in solution. 250 mL of 0.1 M

C u S O_{4}

(aq) is electorlysed by passing a current of 3.512 ampere for 1368 second. After passage of this charge sufficient quantity of

N H_{3}

(aq) is added to electrolysed solution maintaining

[N H_{3}]

=0.10M. If

[C u (N H_{3})_{4}]^{2 +}

is detectable upto its concentration as low as 1

\times 10^{- 5}

, would a blue colour be shown by the electrolysed solution on addition of

N H_{3}

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In the excess of NH3 (aq.),Cu2+ ions forms a deep blue complex ion [Cu(NH3)4]+2 which has Kf=1011 the concentration of Cu2+ ion in solution prepared by adding 5×10−3 moles of CuSO4 to 0.5 L of 0.4 M NH3 (aq) is

The correct option is C 10−5(36)4

In the excess of $N H_{3} (a q .), C u^{2 +}$ ions forms a deep blue complex ion ${[C u {(N H_{3})}_{4}]}^{+ 2}$ which has $K_{f} = 10^{11}$ the concentration of $C u^{2 +}$ ion in solution prepared by adding $5 \times 10^{- 3}$ moles of $C u S O_{4}$ to $0.5 L$ of $0.4 M N H_{3} (a q)$ is

The correct option is C $\frac{10^{- 5}}{{(36)}^{4}}$