In the expansion of $(1 + 3 x + 2 x^{2})^{6}$ , the coefficient of $x^{11}$ is

144

No worries! We‘ve got your back. Try BYJU‘S free classes today!

288

No worries! We‘ve got your back. Try BYJU‘S free classes today!

216

No worries! We‘ve got your back. Try BYJU‘S free classes today!

576

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $576$
In $(1 + 3 x + 2 x^{2})^{6}$
The only way of getting a term of $x^{11}$ is $(2 x^{2})^{5} (3 x)^{1} (1^{0})$
Therefore the corresponding coefficient will be
$\frac{6!}{5! (1!)} 2^{5} (3)$
$= 6 (32) (3)$
$= 6 (96)$
$= 576$

Suggest Corrections

Similar questions

{(1 + 3 x + 2 x^{2})}^{6}

x^{11}

{(1 + 3 x + 2 x^{2})}^{6}

x^{11}

x^{11}

(1 + 3 x + 2 x^{2})^{6}

x^{11}

(1 + 2 x + 2 x^{2})^{6}

{(1 + 3 x + {2 x}^{2})}^{6}

x^{11}

Join BYJU'S Learning Program