In the expansion of $(1 - x)^{5}$ , coefficient of $x^{5}$ will be

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-1

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-5

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Solution

The correct option is B -1
$(r + 1)$ th term in the expansion of $(1 - x)^{5}$ is,
$T_{r + 1} =^{5} C_{r} (1)^{r} (- x)^{(5 - r)} =^{5} C_{r} (- 1)^{(5 - r)} (x)^{5 - r}$
For coefficient of $x^{5}, 5 - r = 5 \Rightarrow r = 0$
Hence coefficient of $x^{5}$ is, $=^{5} C_{5} (- 1)^{5 - 5} = - 1$

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