In the expansion of (1+x)n.(1+y)n.(1+z)n the sum of the coefficients of the terms of degree r is
A
(nCr)3
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B
3nCr
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C
3×nCr
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D
nC3r
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Solution
The correct option is B3nCr The given expression contains 3n factors Using combination to choose r brackets out of 3n brackets for a term of degree r, we get 3nCr Hence, answer is option B