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Question

In the expansion of (1+x)n(1+y)n(1+z)n, the sum of coefficients of the terms of degree ‘r’ is


A

3nCr

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B

3.nCr

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C

3nC3r

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D

3nC3nr

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Solution

The correct options are
A

3nCr


D

3nC3nr


(1+x)n(1+y)n(1+z)n(nm=0 nCmxm)(ns=0 nCsys)(nt=0 nCtzt)=0r, s, tn nCm nCs nCt XmYsZt

For sum of the coefficients of degree ‘r’, we have m + s + t = r; where, m, s, t are integers greater than or equal to zero. Sum of such coefficients

=m,s,t0m+s+t=rnCm n Cs nCt (this is similar to the number of ways of choosing a total of r balls out of n black, n white, n green balls.) =3nCr


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