In the expansion of (1+x)n if the coefficients of three consecutive terms are in A.P., then n+2 is
A
n2
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B
a perfect square
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C
a perfect cube
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D
none
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Solution
The correct option is B a perfect square Let nCr−1,nCr,nCr+1 be in AP Therefore condition for the following terms to be in A.P is nCr−1+nCr+1=2×nCr On simplifying, we get, (n−2r)2=n+2 ...(i) Hence, n+2 is perfect square. Hence answer is option B.