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Question

In the expansion of (2x28)(x4)2, find the value of constant term.

A
128
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B
128
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C
124
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D
122
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Solution

The correct option is A 128
(2x28)(x4)2
=(2x28)(x22x(4)+42)
=(2x28)(x28x+16)
=2x416x3+32x28x2+64x128
=2x416x3+24x2+64x128
Constant term is 128

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