In the expansion of (2x2−8)(x−4)2, find the value of constant term.
A
−128
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B
128
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C
124
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D
122
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Solution
The correct option is A−128 (2x2−8)(x−4)2 =(2x2−8)(x2−2x(4)+42) =(2x2−8)(x2−8x+16) =2x4−16x3+32x2−8x2+64x−128 =2x4−16x3+24x2+64x−128 Constant term is −128