In the expansion of $(2 x^{2} - 8) (x - 4)^{2}$ , find the value of constant term.

- 128

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128

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124

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122

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Solution

The correct option is A $- 128$
$(2 x^{2} - 8) {(x - 4)}^{2}$
$= (2 x^{2} - 8) (x^{2} - 2 x (4) + 4^{2})$
$= (2 x^{2} - 8) (x^{2} - 8 x + 16)$
$= 2 x^{4} - 16 x^{3} + 32 x^{2} - 8 x^{2} + 64 x - 128$
$= 2 x^{4} - 16 x^{3} + 24 x^{2} + 64 x - 128$
Constant term is $- 128$

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