The correct option is C the sum of last two digits of rational terms is 34
In the expansion of (31/7+51/2)14,
Tr+1= 14Cr(31/7)14−r⋅(51/2)r, r=0,1,2,…,14
= 14Cr 3(2−r7)⋅5r/2
There are only two rational terms, when r=0,14
So, rational terms are, T1=32 and T15=57
Total number of terms =14+1=15
Number of irrational terms =15−2=13
Sum of last two digits of rational terms =32+57=9+_ _ _ 25=_ _ _ 34
Since, total number of terms is 15 i.e. odd,
∴ Middle term =15+12=8