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Question

In the expansion of (513817)1126, the number of integral terms is

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Solution

For the expansion 1126Cr 5(1126r)/3 8r/7
1126r should be a multiple of 3
r=1,4,7,10,.....1123
Also r should be a multiple of 7
r=7,14,21,28,1120
L.C.M of 3 and 7 will be 21
First term is 7 then with the difference of 21 making and A.P.
1120=7+(n1)21
n=54

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