For the expansion 1126Cr 5(1126−r)/3 8r/7
1126−r should be a multiple of 3
r=1,4,7,10,.....1123
Also r should be a multiple of 7
r=7,14,21,28,1120
L.C.M of 3 and 7 will be 21
First term is 7 then with the difference of 21 making and A.P.
1120=7+(n−1)21
n=54