Index of (r+1)th Term from End When Counted from Beginning
In the expans...
Question
In the expansion of (2x2−8)(x−4)2; find Constant term.
A
128
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B
54
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C
−54
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D
−128
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Solution
The correct option is C−128 (2x2−8)(x−4)2 =(2x2−8)(x2−2x(4)+42) =(2x2−8)(x2−8x+16) =2x4−16x3+32x2−8x2+64x−128 =2x4−16x3+24x2+64x−128 Constant term is −128