In the expansion of (1+x)n(1+y)n(1+z)n, then the sum of coefficients of the terms of degree m is
A
(nCm)3
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B
3.(nCm)3
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C
3nCm
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D
(nCm)3m
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Solution
The correct option is B3nCm (1+x)n(1+y)n(1+z)n
=(n∑r=0nCrxr)(n∑s=0nCsys)(n∑t=0nCtzt)
=∑0≤r,s,t≤n(nCr)(nCs)(nCt)xryszt For sum of the coefficients of degree m, we must have r+s+t=m Where r,s,t are integers with r,s,t≥0 Sum of such coefficients =∑r,s,t≥0r+s+t=m(nCr)(nCs)(nCt) =the number of ways of choosing a total number of m balls out of n black, n white and n green balls =3nCm