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Question

In the expansion of (1+x)n, The binomial coefficients of three consecutive terms are respectively 220, 495 and 795, the value

A
10
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B
11
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C
12
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D
13
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Solution

The correct option is C 12
Suppose the three consecutive terms are Tr1,Tr and Tr+1.

Coefficient of these terms are nCr2,nCr1 and nCr respectively.

These coefficient are equal to 220,495 and 792

nCr2nCr1=220495

r1nr+2=49

9r9=4n4r+8

4n+17=13r ------ ( 1 )

Also,

nCrnCr1=792495

nr+1r=85

5n5r+5=8r

5n+5=13r

5n+5=4n+17 [ From ( 1 ) ]

n=12



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