In the expansion of (a2√a+3√aa)n the binomial coefficient of 3rd term is 36. The 7th term is :
A
84a3√a
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B
84a2√a
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C
84a2
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D
84a3
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Solution
The correct option is A84a3√a It is given that : nC2=36 n(n−1)2!=36 n(n−1)=72 n(n−1)=9(8) Hence n=9 Hence T7=9C6(a)152a−4 =9C3a72 =9.8.73!.(a3√a) =84(a3√a)