In the expansion of (x+2x2)15, the term independent of x is
(15−r)(1)+r(−2)=0⇒15−3r=0⇒r=5 Thus term independent of x is =15C5(1)10(2)5=15C525.
In the expansion of (x−13x2)9, the term independent of x is
The term independent of x in the expansion of (1+x+2x3)(3x22−13x)9 is