CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

In the expansion of (x1)(x2).....(x18),the coefficient of x17 is

A
684
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
171
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
171
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
342
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 171
the coefficient of x17 is
(1+2+3+.....+18)=18×192=171

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon