CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the expansion of (x1)(x2)....(x18), the coefficient of x17 is

A
684
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
171
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
171
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
342
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 171
(x1)(x2)(x3)(x3)..............(x18)

=x18(1+2+3+4+........+18)x17+(12+23+...........+181)x16.......

So coefficient of x17 is =(1+2+3+........+18)=18192=171

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Theorem for Any Index
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon