wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the expansion of (x+a)n, if the sum of odd terms be P and sum of even terms be Q. Consider the following statements:

(i) P2Q2=(x2a2)n

(ii) P2+Q2=(x2+a2)n

(iii) 4PQ = (x+a)2n(xa)2n

(iv) P - Q = (xa)n

Then the correct statement are:


A

(i), (iv)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

(i), (iii), (iv)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

(i), (iii)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

(ii), (iii)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

(i), (iii), (iv)


In the expansion of (x+a)n.

P+Q = (x+a)n , P-Q = (xa)n

P2Q2=(x2a2)n

(P+Q)2(PQ)2=4PQ

4PQ=(x+a)2n(xa)2n

But P2+Q2(x2+a2)n.

(i),(iii)and(iv) are correct.


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Product of Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon