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Question

In the expansion of (x+a)n, if the sum of odd terms be P and sum of even terms be Q. Consider the following statements:

(i) P2Q2=(x2a2)n

(ii) P2+Q2=(x2+a2)n

(iii) 4PQ = (x+a)2n(xa)2n

(iv) P - Q = (xa)n

Then the correct statement are:


A

(i), (iv)

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B

(i), (iii), (iv)

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C

(i), (iii)

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D

(ii), (iii)

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Solution

The correct option is B

(i), (iii), (iv)


In the expansion of (x+a)n.

P+Q = (x+a)n , P-Q = (xa)n

P2Q2=(x2a2)n

(P+Q)2(PQ)2=4PQ

4PQ=(x+a)2n(xa)2n

But P2+Q2(x2+a2)n.

(i),(iii)and(iv) are correct.


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