In the experiment given below, if the atmospheric pressure is 76 cm of Hg $(h_{0})$ and the height is 3 cm, find the pressure of the gas in the tube.

76 cm of Hg

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79 cm of Hg

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73 cm of Hg

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75 cm of Hg

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Solution

The correct option is B
79 cm of Hg

The pressure of the gas is given by height (the difference in mercury levels). Atmospheric pressure pushes on the mercury from one direction and the gas in the container pushes from the other direction. In a manometer, since the gas in the bulb is pushing more than the atmospheric pressure, add the atmospheric pressure to the height difference.
The gas pressure in the tube is, P = $h_{0}$ + h = 76 cm of hg + 3 cm = 79 cm of Hg.

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In the experiment given below, if the atmospheric pressure is 76 cm of Hg (h0) and the height is 3 cm, find the pressure of the gas in the tube.

In the experiment given below, if the atmospheric pressure is 76 cm of Hg $(h_{0})$ and the height is 3 cm, find the pressure of the gas in the tube.