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Question

In the experiment of Ohm's law, a potential difference of 5.0V is applied across the end of a conductor of length 10.0cm and diameter of 5.00mm. The measured current in the conductor is 2.00A. The maximum permissible percentage error in the resistivity of the conductor is:


A

7.5

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B

3.9

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C

8.4

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D

3.0

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Solution

The correct option is B

3.9


Step 1: Given Information

Potential difference = 5.0V

Length = 10.0cm

Diameter = 5.00mm

Step 2: Calculate the maximum permissible percentage error in the resistivity of the conductor

Knows, formulas V=IR

R=ρlA

V=IρlA

ρ=VAll

A=πd24

Where, R= Resistance, ρ= Resistivity, l=Length, A= Area,I= Current and V= Potential difference

Therefore,

pp=Vv+II+II+2ddρρ=0.015+0.0012+0.0110+20.0015ρρ=0.02+0.005+0.01+0.004ρρ=0.039

Hence, the correct option is (B).


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