Question

In the experiment to determine speed of sound by resonance tube the difference between first two resonance positions is

• A. equal to wavelength of sound
• B. Three fourth of the wavelength of sound
• C. half the wavelength of sound
• D. One fourth of the wavelength of sound

Answer 1

The correct option is C

half the wavelength of sound

$f=\frac{v}{4l}\Rightarrow l_I=\frac{v}{4f};l_2=\frac{3v}{4f},l_2-l_1=\frac{2v}{4f}=\frac{v}{2f}=\frac{\lambda }{2}$