In the extraction of aluminium metal, one of the process is summarised as follows:
Which of the following entries correctly summarises reagents, electrodes and products of the process?

\begin{matrix} A & B & C & D & E N a O H & A l^{3 +} & H F & N a_{3} A l F_{6} & C a t h o d e \end{matrix}

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\begin{matrix} A & B & C & D & E N a O H & N a A l O_{2} & C O_{2} & N a F & A n o d e \end{matrix}

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\begin{matrix} A & B & C & D & E H_{2} S O_{4} & A l_{2} (S O_{4})_{3} & N H_{3} & N a_{3} A l F_{6} & C a t h o d e \end{matrix}

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\begin{matrix} A & B & C & D & E N a O H & N a A l O_{2} & C O_{2} & N a_{3} A l F_{6} & C a t h o d e \end{matrix}

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Solution

The correct option is D $\begin{matrix} A & B & C & D & E N a O H & N a A l O_{2} & C O_{2} & N a_{3} A l F_{6} & C a t h o d e \end{matrix}$
The hot concentrated bauxite ore $(A l_{2} O_{3} .3 H_{2} O)$ reacts with hot concentrated A (NaOH) to form product B $(N a A l O_{2})$
$(A l_{2} O_{3} .3 H_{2} O) b a u x i t e i m p u r e + 2 N a O H h o t c o n c e n t r a t e d A \to 2 N a A l O_{2} B, a q u e o u s s o l u t i o n + 4 H_{2} O$
When carbon dioxide gas (C) is bubbled to change pH, pure
$A l_{2} O_{3} .3 H_{2} O$ is obtained.
$2 N a A l O_{2} B, a q u e o u s s o l u t i o n C (C O_{2} g a s) - ------ \to A l_{2} O_{3} .3 H_{2} O P u r e$ .
It is then mixed with $N a_{2} A l F_{6}$ and melted at $1000^{o} C$ . Then the electrolysis of the molten material is carried out with carbon electrodes to obtain aluminum at cathode ('E').

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