In the extraction of copper from pyrites, iron is removed as:

F e S O_{4}

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F e S i O_{3}

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{F e}_{3} O_{4}

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{F e}_{2} O_{3}

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Solution

The correct option is B $F e S i O_{3}$
In the extraction of copper from pyrites ( $C u F e S_{2}$ ), iron is removed as slag, ferrous silicate $F e S i O_{3}$
slag. Ferrous oxide reacts with sand (silica) to form ferrous silicate slag.
$F e O + S i O_{2} \to F e S i O_{3}$

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Similar questions

{F e S i O}_{3}

{F e}_{2} O_{3}

{F e}_{3} O_{4}

O_{2}

F e

F e O

{F e}_{2} O_{3}

{F e}_{3} O_{4}

Δ G = - 177 K c a l

(1) 2 F e (s) + \frac{3}{2} O_{2} (g) ⟶ {F e}_{2} O_{3} (s)

Δ G = - 19 K c a l f o r (2) {4 F e}_{2} O_{3} (s) ⟶ {3 F e}_{3} O_{4} (s)

{F e}_{3} O_{4}

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