In the extraction of copper, metal is formed in the Bessemer converter due to a reaction:-

C u_{2} S + 2 C u_{2} O \to 6 C u + S O_{2}

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C u_{2} S \to 2 C u + S

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F e + C u_{2} O \to 2 C u + F e O

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2 C u_{2} O \to 4 C u + O_{2}

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Solution

The correct option is B $C u_{2} S + 2 C u_{2} O \to 6 C u + S O_{2}$
In the extraction of copper, metal is formed in the Bessemer converter due to self reduction.

Reaction:
$C u_{2} S + 2 C u_{2} O ⟶ 6 C u + S O_{2}$

Suggest Corrections

Similar questions

C u_{2} S + 2 C u_{2} O \to 6 C u + S o_{2}

A : F e O + S i O_{2} \to F e S i O_{3}

B : 2 F e S + 3 O_{2} \to 2 F e O + 2 S O_{2}

C : 2 C u_{2} S + 3 O_{2} \to 2 C u_{2} O + 2 S O_{2}

D : 2 C u_{2} O + C u_{2} S \to 6 C u + S O_{2}

Select reactions actually taking place :

- I

- II

\begin{matrix} List - I & List - II (I) N i Impure + 4 C O 330 K - -- \to N i (C O)_{4} 450 K - -- \to N i pure + 4 C O & (P) Leaching (II) 4 A u + 4 N a C N + O_{2} + 2 H_{2} O - ---- \to - 4 K O H & (Q) Mond's reduction 4 N a [A u (C N)_{2}] Soluble Z n - \to 2 N a [Z n (C N)_{4}] + 4 A u (III) T i C l_{4} + 2 M g \to T i + 2 M g C l_{2} & (R) Auto reduction (IV) 2 C u_{2} S + 30_{2} \to 2 C u_{2} O + 2 S O_{2} & (S) Kroll process C u_{2} S + 2 C u_{2} O \to 6 C u + S O_{2} \end{matrix}

-I

-II

C u_{2} S

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