In the $F_{2}$ generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are

Phenotypes-4; Genotypes-16

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Phenotypes-9; Genotypes-4

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Phenotypes-4; Genotypes-8

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Phenotypes-4; Genotypes-9

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Solution

The correct option is B Phenotypes-4; Genotypes-9
The dihybrid cross is a cross between two different genes means a cross between two different characters.
In F2 generation - 4 phenotypes are present (yellow round, Green round, yellow wrinkled and green wrinkled)
And 9 genotypes are present (1:2:1:2:4:2:1:2:1)
So the correct answer is "Phenotypes-4, Genotypes-9".

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How many different phenotypes and genotypes are obtained in Mendel’s $F_{2}$ generation of dihybrid cross?

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