In the fig 2.49, show that $△$ AOB $~$ $△$ MOP using the information given.

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Solution

$In △ AOB and △ MOP, we have : ∠ AOB = ∠ MOP (Vertically opposite angles) and \frac{6}{9} = \frac{8}{12} [\frac{6}{9} = \frac{2}{3} = \frac{8}{12}] i . e ., \frac{OB}{OP} = \frac{AO}{MO} Thus, △ AOB ≅ △ MOP (SAS similarity test)$

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In the fig 2.49, show that △AOB ~△MOP using the information given.

In △AOB and △MOP, we have:∠AOB = ∠MOP (Vertically opposite angles)and 69= 812 69=23=812i.e., OBOP = AOMOThus, △AOB≅△MOP (SAS similarity test)

In the fig 2.49, show that $△$ AOB $~$ $△$ MOP using the information given.

$In △ AOB and △ MOP, we have : ∠ AOB = ∠ MOP (Vertically opposite angles) and \frac{6}{9} = \frac{8}{12} [\frac{6}{9} = \frac{2}{3} = \frac{8}{12}] i . e ., \frac{OB}{OP} = \frac{AO}{MO} Thus, △ AOB ≅ △ MOP (SAS similarity test)$