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Question

In the fig 2.58, if the lines PQ and RS intersect at Point T such that PRT = 40°, RPT = 92° and TSQ = 70° find SQT.

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Solution

In PRT, we have:P+R+T = 180°92°+40°+T = 180°T = 48°RTP=STQ=48° (Vertically opposite angles)In STQ, we have:T+S+Q =180°48°+70°+Q =180°Q = 62°Thus, SQT = 62°

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