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Question

In the fig 2.59, if PQ PS, PQ || SR, SQR = 30°, QRT = 65° then find the values of x, y, and z.

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Solution

Given: SQR=30° and QRT=65°QRT+QRS = 180° (Linear pair)65°+QRS = 180°QRS =115° In QRS, we have:SQR+QRS+QSR = 180°30°+115°+QSR = 180°QSR =35° ...(i)As x=QSR =35° (PQSR) In PQS, we have:x+y+90° =180°35°+y+90°=180° from(i)y = 55° ...(ii)As PSV is a straight line, we have:y+QSR+z =180°55°+35°+z = 180° [From(i) and (ii)]z = 90°

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