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Question

In the fig. 3.10, seg AO seg OD, seg BO seg OC Then show that ABC DCB

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Solution

Given : seg AO seg OD, seg BO seg OCi.e. AO=OD, BO= OCIn OBC,OBC = OCB (OB = OC) ....(i)In ABC and DCB,AO+OC = DO+OB AO = OD, BO =OC AC = DB,OBC = OCB , from(i)BC = BC (common)ABC DCB (by SAS congruency test)Thus, ABC DCB (by c.a.c.t) .

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