In the fig. below, if AB∥CD,∠APQ=50∘ and
∠PRD=127∘,
find x and y.
50o, 67o
50o, 77o
77o, 87o
77o, 97o
∵AB∥CD
∠APQ=∠PQR
(Alternate interior angles of transversal PQ)
⇒x=50∘
⇒∠APR=∠PRD
(Alternate interior angles of transversal PR)
⇒y+50∘=127∘
⇒y=127∘−50∘
=77∘
In the fig. below, if AB || CD, ∠APQ = 50∘ and ∠PRD = 127∘, find x and y.
In the figure if AB ||CD, ∠APQ = 50o and ∠PRD = 127o then y is equal to