In the fig. If AB || CD, EF ⊥ CD and ∠GED=1260, find ∠AGE,∠GEF and ∠FGE.
Given :AB∥CD
EF⊥CD
⇒∠FED=90∘
Given:∠GED=126∘
⇒∠GEF=∠GED−∠FED=126∘−90∘
∴∠GEF=36∘
In △FGE,∠GFE+∠GEF+∠EGF=180∘ by angle sum property.
⇒90∘+36∘+∠EGF=180∘
⇒∠EGF=180∘−126∘=66∘
∠AGE=∠AGF-∠EGF
⇒∠AGE=180∘−66∘=114∘
∴∠AGE=114∘,∠GEF=36∘ and ∠FGE=66∘