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Question

In the fig, if the lines PQ and RS intersect at point T such that PRT=40o,RPT=92o and TSQ=70o find SQT (in degrees).
184128_cd28dbc5c69a4fcda1e8c5ffcc81e57d.png

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Solution

In PRT,
PRT+RTP+RPT=180o
40o+92o+RTP=180o
RTP=48o
In PRT and TSQ,
PTR=STQ=48 (Vertically opposite angles)
In STQ,
STQ+SQT+TQS=180o
48o+70o+SQT=180o
SQT=62o

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