In the fig, if the lines PQ and RS intersect at point T such that ∠PRT=40o,∠RPT=92o and ∠TSQ=70o find ∠SQT (in degrees).
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Solution
In △PRT, ∠PRT+∠RTP+∠RPT=180o 40o+92o+∠RTP=180o ⇒∠RTP=48o In △PRT and △TSQ, ∠PTR=∠STQ=48∘ (Vertically opposite angles) In △STQ, ∠STQ+∠SQT+∠TQS=180o 48o+70o+∠SQT=180o ∠SQT=62o