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Question

In the figure 1.75 BAC = 75°, ABC = 35°. Find the measures of BAZ, CBX, and ACY.

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Solution

Given:
BAC = 75°ABC = 35°


Here, BAZ + BAC = 180° (Linear pair)BAZ + 75° = 180° (Given)BAZ = 105°Similarly,ABC + CBX = 180° (Linear pair)35° + CBX = 180° (Given)CBX = 145°Now, ACY=BAC+ABC (Exterior angle property)ACY = 75°+35° = 110°

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