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Second Law of Motion

In the figure...

Question

In the figure, a ball of mass m is tied with two strings of equal length as shown. If the rod is rotated with angular velocity $ω$ . Select the correct relationship.

T_{1} > T_{2}

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T_{2} > T_{1}

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T_{1} = T_{2}

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T_{1} = \frac{T_{2}}{6}

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Solution

The correct option is A $T_{1} > T_{2}$
required force for circular motion
$m ω^{2} r = T_{1} s i n θ - m g - T_{2} s i n θ a s T_{1} = T_{2} + (\frac{m g + m ω^{2} r}{s i n θ}) a l l v a l u e s a r e p o s t i v e h e r e ∴ T_{1} > T_{2}$

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