wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure, a man of true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string with a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is:
992195_8ed9f99cbc7c44e589f2864070f42d3f.png

A
MmM+m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
MmMm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
depends on g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A MmM+m
weight measure by weighting machine =M(ga)
from F.B.D of lift
T=m(ga).....(1)
from F.B.D of pully
T=ma......(2)
ma=m(ga)
mg=ma+ma
mg=a(m+m)
a=Mm+mg
weight=m(ga)
=m(gmgm+m)
=m(m+mm)gm+m
w=mmgm+m
mass=mmm+m

1438992_992195_ans_35e54a54b59b4f51af5d21434683ba04.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nomenclature of Saturated Hydrocarbons
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon