Question

In the figure AB and CD are extended to intersect at P. If AB = 5, BP = 3, PD = 2 then find CD.

• A. 10
• B. 9
• C. 2
• D. 8

Answer 1

The correct option is A 10

$PA=8,PB=3,PD=2$

$PA\times PB=PC\times PD$

$8\times 3=PC\times 2$

$PC=12$
So,
$CD=PC-PD$
$=12-2$
$=10$