Question

In the figure, $AB||CD$, find $x$.

Answer 1

Let us draw a line $EF$ parallel to the lines $AB$ and $CD$.

Then $\angle BPF=\angle ABP={48}^o$ [ alternate angle].......(1).

Also, $\angle CPF=\angle PCD={24}^o$ [ alternate angle]......(2).

Now

$\angle BPC=\angle BPF+\angle CPF={48}^o+{24}^o={72}^o$.

Then $x={360}^o-{72}^o={288}^o$.