In the figure- AB CD- If - 2-2 x -30- - 4- x -2 y o and - 6-3 y -10- the measure of - 5 isA- 40-B- 50-C- 90-D- 60-

The correct option is B 50o2 = 4 …(vertically opposite angles), 4 = 6 …(Alternate angles) (2x + 30) = (x + 2y) …(1) (x+ ...

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Standard IX

Mathematics

Parallel Lines with Transversal

In the figure...

Question

In the figure, AB ║ CD. If ∠2 = (2x + 30)^o, ∠4 = ( x + 2y)^oand ∠6 = (3y+10)^o the measure of ∠5 is

40^o

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90^o

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60^o

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50^o

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Solution

The correct option is D
50^o

2 = 4 …(vertically opposite angles),

4 = 6 …(Alternate angles)

(2x + 30) = (x + 2y) …(1)

(x+2y) = (3y +10) …(2)

From (1) and (2)

x= 50, y = 40.

Then 5 = 180^o - 6 = 50^o

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In the figure, AB ║ CD. If ∠2 = (2x + 30)o, ∠4 = ( x + 2y)o and ∠6 = (3y+10)o the measure of ∠5 is

The correct option is D 50o2 = 4 …(vertically opposite angles), 4 = 6 …(Alternate angles) (2x + 30) = (x + 2y) …(1) (x+2y) = (3y +10) …(2) From (1) and (2) x= 50, y = 40. Then 5 = 180o - 6 = 50o

In the figure, AB ║ CD. If ∠2 = (2x + 30)^o, ∠4 = ( x + 2y)^oand ∠6 = (3y+10)^o the measure of ∠5 is

The correct option is D
50^o

2 = 4 …(vertically opposite angles),

4 = 6 …(Alternate angles)

(2x + 30) = (x + 2y) …(1)

(x+2y) = (3y +10) …(2)

From (1) and (2)

x= 50, y = 40.

Then 5 = 180^o - 6 = 50^o