Question

In the figure, AB || DC, then the measure of $\angle D$ is equal to

• A. ${285}^{\circ }$
• B. ${105}^{\circ }$
• C. ${75}^{\circ }$
• D. ${110}^{\circ }$

Answer 1

The correct option is B ${105}^{\circ }$

Since, AB || DC and AD is transversal
$\Rightarrow \angle A+\angle D={180}^{\circ }$ [Co-interior angles are supplemetary]
$\Rightarrow \angle D={180}^{\circ }-{75}^{\circ }$
$\Rightarrow \angle D={105}^{\circ }$
Hence, the measure of $\angle Dis{105}^{\circ }$