Question

In the figure, AB is a diameter of the circle such that $\angle A={35}^{o}and\angle Q={25}^o$, find $\angle PBR$.

Answer 1

In the figure, AB is the diameter of the circle such that $\angle A={35}^{o}and\angle Q={25}^o$.

Now, $\angle APB={90}^o$ (Angle in a semi-circle)

So, $\angle BPQ={90}^o$ (Linear pair)

and in $\Delta PQB$, Ext. $\angle PBR=\angle BPQ+\angle PQB$

$={90}^o+{25}^o={115}^o$

$\therefore \angle PBR={115}^o$