In the figure- AB is a straight line- If - AOC-50- and - DOB-60- then find x-

The correct option is A 7050^∘+60^∘+x^∘=180^∘ [Angles on a straight line add to 180^∘ nbsp;] 110^∘+x^∘=180^∘ ∴ x= 70^∘ ...

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Byju's Answer

Standard IX

Mathematics

Axioms

In the figure...

Question

In the figure, AB is a straight line. If $∠ A O C = 50^{\circ}$ and $∠ D O B = 60^{\circ}$ , then find x.

70

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Solution

The correct option is A 70
$50^{\circ} + 60^{\circ} + x^{\circ} = 180^{\circ}$
[Angles on a straight line add to $180^{\circ}$ ]

$110^{\circ} + x^{\circ} = 180^{\circ}$

$∴ x = 70^{\circ}$

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Similar questions

In the given figure, AB is a straight line. If $∠ A O C = 50^{\circ}$ and $∠ D O B = 60^{\circ}$ , then x = ______ .

Q. In the figure given below, AB is a straight line. If

∠ A O C = 50 °

and

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, then find the value of x.

In the figure below, straight lines AB and CD intersect at O. If $∠$ AOC + $∠$ BOE = $70^{\circ}$ and $∠$ BOD = $40^{\circ}$ , find (2 $∠$ BOE).

Q. In the given figure, AOB is a straight line. If ∠AOC = (3x − 10)°, ∠COD = 50° and ∠BOD = (x + 20)°, then ∠AOC = ?
(a) 40°
(b) 60°
(c) 80°
(d) 50°

In the given figure, AOB is a straight line. If $∠ A O C = (3 x - 10)^{\circ}$ , \angle COD = 50^{\circ}\) and $∠ B O D = (x + 20)^{\circ}$ then $∠ A O C = ?$

(a) $40^{\circ}$

(b) $60^{\circ}$

(d) $50^{\circ}$

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In the figure, AB is a straight line. If ∠AOC=50∘ and ∠DOB=60∘, then find x. 70

The correct option is A 7050∘+60∘+x∘=180∘ [Angles on a straight line add to 180∘ ] 110∘+x∘=180∘ ∴x=70∘

In the figure, AB is a straight line. If $∠ A O C = 50^{\circ}$ and $∠ D O B = 60^{\circ}$ , then find x.

70

The correct option is A 70
$50^{\circ} + 60^{\circ} + x^{\circ} = 180^{\circ}$
[Angles on a straight line add to $180^{\circ}$ ]

$110^{\circ} + x^{\circ} = 180^{\circ}$

$∴ x = 70^{\circ}$