In the figure, AB is parallel to DC and AD is parallel to BC,
If ∠ADC=105∘, ∠CBE=? is
75∘
∠DAB=180∘−∠ADC=180∘−105∘=75∘ [Co-interior angles are supplementary]
∠DAB=∠CBE=75∘ [Corresponding angles are equal as AD is parallel to BC]
Hence, ∠CBE=75∘.