Question

In the figure $AB\parallel CD$. Then two triangles with same area are $ABD$ and $ABC$.

• A. True
• B. False

Answer 1

The correct option is A True

Here, $ABCD$ is a quadrilateral.

$AB\parallel CD$ [ Given ]

One pair of quadrilateral is parallel.

$\therefore$ $ABCD$ is a trapezium.

Here, $△ABD$ and $△ABC$ are situated between parallel lines $AB$ and $CD$ having same base $AB$.

We know that, the triangles having same base and situated between a parallel lines are equal in area.

$\therefore$ $ar\left(△ABD\right)=ar\left(△ABC\right)$