In the figure, AB = $\sqrt{} u n i t s$

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Solution

x- Coordinate is same for A and D and B and C, so the distance will simply be difference between the y–coordinates. y-Coordinate is same for C and D, so the distance will simply be the difference between x–coordinates.

Therefore, AD = 5 - 0 = 5 units

DC = 5 – 2 = 3 units

BC = 3 – 0 = 3 units

AB = $\sqrt{(5 - 3))^{2} + (3 - 5)^{2}}$
= $\sqrt{9 + 4}$
= $\sqrt{13} u n i t s$

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