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Question

In the figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region. [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Mark

Area of quadrant
=90360×π×14×14=153.94 cm2

Area of ΔABC=0.5×142=98 cm2

The diameter =14×2=19.8 cm.

Area of semi-circle
=0.5 π×9.92=153.95 cm2

The area of segment
=153.9498=55.94 cm2

The required area
=153.9555.94=98.01 cm2.


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